47 lines
1.7 KiB
Python
47 lines
1.7 KiB
Python
import PySimpleGUI as sg
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import PySimpleGUIdebugger # STEP 1
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"""
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Demo program that shows you how to integrate the PySimpleGUI Debugger
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into your program.
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In this example, the debugger is not started initiallly. You click the "Debug" button to launch it
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There are THREE steps, and they are copy and pastes.
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1. At the top of your app to debug add
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import PySimpleGUIdebugger
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2. Initialize the debugger at the start of your program by calling:
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PySimpleGUIdebugger.initialize()
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3. At the top of your app's Event Loop add:
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PySimpleGUIdebugger.refresh(locals(), globals())
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"""
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layout = [
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[sg.T('A typical PSG application')],
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[sg.In(key='_IN_')],
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[sg.T(' ', key='_OUT_')],
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[sg.Radio('a',1, key='_R1_'), sg.Radio('b',1, key='_R2_'), sg.Radio('c',1, key='_R3_')],
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[sg.Combo(['c1', 'c2', 'c3'], size=(6,3), key='_COMBO_')],
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[sg.Output(size=(50,6))],
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[sg.Ok(), sg.Exit(), sg.B('Debug')],
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]
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window = sg.Window('This is your Application Window', layout)
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counter = 0
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timeout = 100
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debug_started = False
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while True: # Your Event Loop
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if debug_started:
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debug_started = PySimpleGUIdebugger.refresh(locals(), globals()) # STEP 3 - refresh debugger
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event, values = window.Read(timeout=timeout)
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if event in (None, 'Exit'):
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break
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elif event == 'Ok':
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print('You clicked Ok.... this is where print output goes')
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elif event == 'Debug' and not debug_started:
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PySimpleGUIdebugger.initialize() # STEP 2
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debug_started = True
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counter += 1
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window.Element('_OUT_').Update(values['_IN_'])
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window.Close()
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