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@ -2,26 +2,47 @@
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import queue
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import threading
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import time
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import PySimpleGUI as sg
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# Put your long-running code in here
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"""
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Demo on how to add a long-running item to your PySimpleGUI Event Loop
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If you want to do something that takes a long time, and you do it in the
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main event loop, you'll quickly begin to see messages from windows that your
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program has hung, asking if you want to kill it.
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The problem is not that your problem is hung, the problem is that you are
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not calling Read or Refresh often enough.
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One way through this, shown here, is to put your long work into a thread that
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is spun off, allowed to work, and then gets back to the GUI when it's done working
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on that task.
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If you have multiple long tasks to run, then you'll want a more sophisticated
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format to your messages going back to the GUI so you'll know which task finished
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"""
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# ---------------------------------------
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# Put your long-running code in here #
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# ---------------------------------------
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def worker_thread(thread_name, gui_queue):
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print('Starting thread - {} '.format(thread_name))
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# this is our "long running function call"
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time.sleep(5) # sleep for a while
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print('Ending thread - {} '.format(thread_name))
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# at the end of the work, before exiting, send a message back to the GUI indicating end
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# in this case, we're using a simple string
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gui_queue.put('{} - done'.format(thread_name)) # put a message into queue for GUI
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###### ## ## ####
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######## ## ## ####
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## ## ## ## ##
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## ## ## ##
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## #### ## ## ##
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## ## ## ## ##
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## ## ## ## ##
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###### ####### ####
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######## ######### ####
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def the_gui(gui_queue):
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@ -32,29 +53,27 @@ def the_gui(gui_queue):
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window = sg.Window('Multithreaded Window').Layout(layout)
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# --------------------- EVENT LOOP ---------------------
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message = None
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count = 0
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while True:
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event, values = window.Read(timeout=100) # wait for up to 100 ms for a GUI event
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if event is None or event == 'Exit':
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break
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if event == 'Go':
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if event == 'Go': # clicking "Go" starts a long running work item by starting thread
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window.Element('_OUTPUT_').Update('Starting long work %s'%count)
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# simulate STARTING long run by starting a thread
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# STARTING long run by starting a thread
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threading.Thread(target=worker_thread, args=('Thread %s'%count, gui_queue,), daemon=True).start()
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count += 1
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# --------------- Loop through all messages coming in from threads ---------------
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try: # see if something has been posted to Queue
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message = gui_queue.get_nowait()
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except queue.Empty: # get_nowait() will get exception when Queue is empty
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pass # nothing in queue so do nothing
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# --------------- Read next message coming in from threads ---------------
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try:
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message = gui_queue.get_nowait() # see if something has been posted to Queue
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except queue.Empty: # get_nowait() will get exception when Queue is empty
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message = None # nothing in queue so do nothing
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# if message received from queue, display the message in the Window
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if message is not None:
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# this is the place you would execute code at ENDING of long running task
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window.Element('_OUTPUT_').Update(message)
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window.Refresh() # do a refresh because could be showing multiple messages before next Read
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message = None
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# if user exits the window, then close the window and exit the GUI func
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window.Close()
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